Solution:
1. Bd3 (1. Kc3 $2 Nd3 $19) (1. Ka4 $2 Nd3 2. Bxd3 e1=Q
3. Rb3 {= Wissmann} 3... Qd1 $19 (3... Qe8+ $19) (3...
Qh4+ $19)) 1... Nxd3 (1... b1=Q+ 2. Bxb1 Kxb1 3. Re8
$11) 2. Kc2 {dreigt 3.Ta8 mat} 2... Nc1 (2... e1=N+
3. Kd2 b1=Q 4. Rxb1+ Kxb1 $11) (2... Ne1+ 3. Kd2 $11)
3. Rxb2 e1=Q 4. Rb1+ Ka2 5. Ra1+ Kxa1 {pat} 1/2-1/2
Comments (1):
Similar diagrams (1):
References:
